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Find two consecutive even integers such that twice the smaller is 16 more than the larger
5 months ago
Q:
find two consecutive even integers such that twice the smaller is 16 more than the larger
Accepted Solution
A:
Define x:
Let one of the numbers be x.
The other number is x + 2
Construct equation:
twice the smaller is 16 more than the larger
⇒2x = x + 2 - 16
Solve x:
2x = x + 2 - 16
x = -14
Find the two numbers:
Smaller number = x = -14
Larger number = x + 2 = -12
Answer: The two numbers are -14 and -12